← Hydrology & Irrigation Engineering

Hydrographs & Unit Hydrograph

Hydrograph components — rising limb, crest, recession limb, lag time and time base; factors affecting hydrograph shape; baseflow separation methods and recession constant; effective rainfall hyetograph; unit hydrograph theory — definition, assumptions, limitations, derivation from isolated storms and use by superposition; S-curve and change of unit duration; synthetic unit hydrographs (Snyder, SCS); instantaneous unit hydrograph — with solved numericals.

📑 Contents (10 sections)

Last reviewed 16 Sept 2026 · 8 min read

The hydrograph

A hydrograph is a graph of discharge against time at a stream section. A storm hydrograph has:

Part Description
Rising limb (concentration curve) Discharge increases as runoff from progressively larger parts of the catchment arrives
Crest segment (peak) Maximum discharge; occurs when runoff from all parts contributes most
Recession limb (falling limb) Withdrawal of water from storage in the catchment and channels; independent of storm characteristics
Point of inflection on recession Marks the end of direct runoff (approximately)

Time parameters:

  • Time to peak — from the start of effective rainfall to the peak.
  • Basin lag — from the centroid of effective rainfall to the peak (sometimes to the centroid of the hydrograph).
  • Time of concentration — time for runoff from the hydraulically most remote point to reach the outlet.
  • Time base — duration of direct runoff.

Factors affecting the hydrograph shape

  • Catchment shape — fan-shaped catchments: high, sharp peaks; fern-leaf (elongated): flatter, delayed hydrographs.
  • Size — large catchments have longer time bases and lower peaks per unit area.
  • Slope — steep channels and land slopes give steep rising limbs.
  • Drainage density — high density gives quicker, peakier response.
  • Land use — forests and vegetation flatten the hydrograph; urban areas sharpen it.
  • Storm characteristics — intensity, duration, areal distribution and direction of movement: a storm moving downstream gives a higher peak than one moving upstream.

Baseflow separation

To obtain the direct runoff hydrograph (DRH), baseflow is subtracted:

  1. Straight-line method — join the start of the rising limb to a point on the recession limb days after the peak.
  2. Fixed base method — extend the pre-storm recession to below the peak, then join to the point days after the peak.
  3. Variable slope method — separate groundwater recession curves before and after the storm.

Recession curve: , with recession constant (separately for surface, interflow and baseflow storage).

Effective rainfall hyetograph

Effective rainfall (rainfall excess) = rainfall − losses (using the φ-index or other loss models). Its volume equals the volume of direct runoff. The ERH plotted against time is the input to unit hydrograph computations.

Unit hydrograph

DefinitionUnit hydrograph (Sherman, 1932)

The D-hour unit hydrograph is the direct runoff hydrograph resulting from one unit (1 cm) depth of effective rainfall occurring uniformly over the catchment at a constant rate for D hours.

Assumptions

  1. Time invariance — the DRH for a given effective rainfall is always the same regardless of when it occurs.
  2. Linear response — ordinates are proportional to the effective rainfall depth (proportionality), and hydrographs from successive storms can be added (superposition).
  3. Effective rainfall uniformly distributed over the catchment and within the duration.

Limitations

  • Precipitation must be nearly uniform — so the method is best for catchments of moderate size (large catchments are subdivided; the upper limit is often quoted as about 5000 km²).
  • Not suitable when snowmelt or large channel storage dominate, or for very small plots.
  • The effective rainfall must have a duration close to the unit duration used.

Area under the unit hydrograph

The volume of direct runoff equals 1 cm over the catchment:

Derivation from an isolated storm

  1. Select an isolated, uniform storm of duration about D hours.
  2. Separate baseflow → DRH.
  3. Compute the effective rainfall depth = DRH volume ÷ catchment area.
  4. UH ordinate = DRH ordinate ÷ effective rainfall depth (cm).
  5. Average the unit hydrographs from several storms (average peak and time to peak; adjust shape to keep unit volume).

Using the unit hydrograph

For effective rainfalls of cm in successive D-hour blocks, the DRH is obtained by multiplying the UH by each depth, lagging each by D hours, and adding. Baseflow is then added to get the flood hydrograph.

Changing the unit duration

Method of superposition

A nD-hour UH (n integer) = sum of n D-hour UHs lagged successively by D hours, divided by n.

S-curve method

FormulaS-curve (S-hydrograph)

The S-curve is the hydrograph from a continuous effective rainfall of 1 cm per D hours — the sum of an infinite series of D-hour UHs lagged by D hours. It rises to an equilibrium discharge:

T-hour UH from a D-hour S-curve:

The S-curve method works for any T (larger or smaller than D, not necessarily a multiple).

Synthetic unit hydrographs

For ungauged catchments, UH parameters are related to catchment characteristics:

  • Snyder's method: basin lag ( = main stream length, = distance along the stream to the point nearest the catchment centroid, in km; in h); peak discharge (m³/s per cm).
  • SCS dimensionless unit hydrograph — time to peak ; peak (m³/s per cm, A in km², in h); time base ≈ 5 for the curvilinear form (2.67 for the triangular form).
  • Regional methods — in India, the Central Water Commission's flood estimation reports give regional synthetic UH relations for hydro-meteorological sub-zones.

Instantaneous unit hydrograph (IUH)

The UH as — the response to 1 cm of effective rainfall applied instantaneously. It depends only on catchment characteristics. Conceptual models: Nash's cascade of linear reservoirs, Clark's model (time–area diagram routed through a linear reservoir). A D-hour UH is obtained by routing/averaging the IUH (or from its S-curve).

Worked examples

Worked ExampleExample 1 — catchment area from a UH

The ordinates of a 4-hour UH at 4-hour intervals are 0, 20, 60, 40, 20, 10, 0 m³/s. Find the catchment area.

Solution. → (Check: equilibrium S-curve discharge m³/s = sum of the UH ordinates ✓)

Worked ExampleExample 2 — flood hydrograph from the UH

For the same catchment, a storm gives 3 cm effective rainfall in the first 4 hours and 2 cm in the next 4 hours. Baseflow is 10 m³/s. Find the flood hydrograph and its peak.

Solution.

Time (h) UH 3 × UH 2 × UH (lagged 4 h) DRH Flood (+10)
0 0 0 – 0 10
4 20 60 0 60 70
8 60 180 40 220 230
12 40 120 120 240 250
16 20 60 80 140 150
20 10 30 40 70 80
24 0 0 20 20 30
28 – – 0 0 10

Peak flood = 250 m³/s at 12 h. Volume check: m³ = 5 cm over 216 km² ✓

Worked ExampleExample 3 — baseflow separation time

Find for a catchment of 1000 km².

Solution.

Worked ExampleExample 4 — deriving a UH

A 6-hour storm producing 2.5 cm of effective rainfall gives a DRH with a peak ordinate of 150 m³/s. What is the peak of the 6-hour UH?

Solution. UH peak

Frequently tested points

  • Hydrograph: rising limb, crest, recession; recession depends only on catchment storage.
  • Fan-shaped catchment and downstream-moving storm → higher peak.
  • days; recession .
  • UH: 1 cm effective rain, uniform, D hours; assumptions of linearity (proportionality, superposition) and time invariance.
  • Area under UH = 1 cm × A: .
  • S-curve equilibrium ; .
  • Snyder ; IUH is the UH with zero duration.
Common MistakeCommon mistakes
  • Adding baseflow before multiplying by rainfall depth (convert only the DRH).
  • Lagging subsequent rainfall blocks by the wrong interval (lag equals the UH duration).
  • Forgetting the factor when deriving a T-hour UH from an S-curve.
Revision SummaryChapter summary
  1. Hydrograph shape reflects both storm and catchment characteristics.
  2. Baseflow separation gives the direct runoff hydrograph; its volume equals effective rainfall.
  3. The unit hydrograph converts effective rainfall to direct runoff by proportionality and superposition.
  4. Superposition and S-curves change the unit duration; synthetic UHs and the IUH serve ungauged and conceptual analyses.

This chapter is in the syllabus of

Open an exam to see where this chapter sits in its syllabus, and to practise it.

✅ Free — no sign-up needed

How ready are you for Hydrology & Irrigation Engineering?

Ten questions from the real syllabus, about five minutes. You will see your score and which subject is holding you back — before you create any account.

10 questions · no timer · no payment